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Area of a triangle =
Let,
Height of one triangle = h1 and base = b1
Height of second triangle = h2 and base = b2
Therefore,
Area of one triangle:Area of second traingle= 2:3
1/2×b1×h1 : 1/2×b2×h2 = 2:3
Since h1=h2
b1 : b2 = 2:3
Given b1 = 6 cm
6 cm : b2 = 2:3
b2 × 2 = 6 cm×3
b2 = 18 cm/2
b2= 9 cm
Base of bigger triangle = 9 cm
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