plz answer the question using steps..
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Assuming the question as find the value of x3-8y3-36xy-216 at x=2y+6
Solution:
Put x = 2y + 6 in x3-8y3-36xy-216
∴ The given polynomial becomes, (2y+6)3 – 8y3 – 36(2y+6)y – 216
= 8y3 + 72y2 + 216y + 216 – 8y3 – 72y2 – 216y – 216 [Since (a+b)3 = a3 + 3a2b + 3ab2 + b3]
= 0
Solution:
Put x = 2y + 6 in x3-8y3-36xy-216
∴ The given polynomial becomes, (2y+6)3 – 8y3 – 36(2y+6)y – 216
= 8y3 + 72y2 + 216y + 216 – 8y3 – 72y2 – 216y – 216 [Since (a+b)3 = a3 + 3a2b + 3ab2 + b3]
= 0
lucky306:
thnx for the help
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