Question

Plz answer thia ques....​

Answer 1

Step-by-step explanation:

2x-3= 3 × (5x-10)

10

2x-3=3x -3

10

2x-3=3x-30

10

(2x-3)(10)=3x-30

20x-30=3x-30

20x-3x=-30+30

17x=0

x=0

Answer 2

Question

Find 'x' in the equation ⇒ $2x-3=\frac{3}{10} \times (5x-10)$

$\rule{300}{1}$

Answer

Let's solve your equation step-by-step.

$2x-3=\frac{3}{10} \times (5x-10)$

Step 1: Simplify both sides of the equation.

$2x-3=\frac{3}{10} \times (5x-10)$

(Distribute)

$2x+-3=(\frac{3}{10})(5x)+(\frac{3}{10})(-10)$

$2x+-3=\frac{3}{2}x+-3$

$2x-3=\frac{3}{2}x-3$

Step 2: Subtract $\frac{3}{2}x$ from both sides.

$2x-3-\frac{3}{2}x =\frac{3}{2}x-3-\frac{3}{2}x$

$\frac{1}{2}x-3=-3$

Step 3: Add 3 to both sides.

$\frac{1}{2}x-3+3=-3+3$

$\frac{1}{2}x =0$

Step 4: Multiply both sides by 2.

$2\times \frac{1}{2}x =2\times 0$

$x=0$

Verification if x = 0.

$2x-3=\frac{3}{10} \times (5x-10)$

$(2\times 0) -3=\frac{3}{10} \times ((5\times 0) -10)$

$0-3=\frac{3}{10} \times (0-10)$

$-3=\frac{3}{10} \times -10$

$-3=-3$

$\bf \therefore x=0\ in \ the \ equation \ 2x-3=\frac{3}{10} \times (5x-10)$

$\rule{300}{1}$