Question

PLZ ANSWER THIS
DO WE HAVE TO FIRST FIND MEASURES OF BASE ANGLES IN Triangle CPQ.
If not then what is the correct solution.
ANSWERS EXCEPT SPAM ONES WILL BE APPRECIATED

Answer 1

Given-

seg SO is perpendicular seg PQ and

seg BQ is perpendicular seg PQ

To prove -

seg CP is congruent seg CQ

Construction -

join CP, CT ,BQ

Proof-

seg AP perpendicular seg PQ

seg CT perpendicular seg PQ

seg BQ perpendicular seg PQ

AC/CB = PT/TQ ....i)..properties of three parallel lines

But,

AC =CB...radio of sana circle

AC/CB = 1....ii)

from i)

PT / TQ =1

hense PT = TQ.....iii)

In triangle CTP and triangle CTQ,

seg CT congruent seg CT ....commen side

angle CTP congrount angle CTQ .....each 90

PT = TQ ....from iii)

triangle CTP congrount triengle CTQ ...S-A-S test

hense,

seg CO congrount seg CQ...C.S.CT

hope this help u

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