Question

Plz answer this fast

Answer 1

Answer:

Step-by-step explanation:

As n=k

Sk = k/2 (2a+(k-1)d)

3k^2 - k = k/2 (2a+6k-6)

2(3k^2 - k) = 2ak +6k^2 -6k

6k^2 -2k = 2ak +6k^2 -6k

-2k +6k = 2ak

4k = 2ak

4k/2k = a

a = 2

Therefore the first term is 2