Question

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Two copper conductors one has length l and area a the other has length 2L area a bi to find the resistance and resistivity of both the wires? ​

Answer 1

Explanation:

Answer:

What is the unit of length ? Sorry for any inconivinience.

Explanation:

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Answer 2

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Let the resistivity of both the wires be 'ρ'. The resistance of the wire A is given as

RA = ρ1/πr²

The Resistance of the wires B is given as

RB = ρ21/π2r² = ρ1/2πr²

Now when the resistance are connected in series is R = RA + RB. That is, R = 3/2 (ρ1/πr²)

So, the required ratio is

R:RA = 3/2(ρ1/πr²) : ql/πr²

Therefore, R : RA = 3:2

Hence, the ratio of the resistances in series and only wire A is 3/2.

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