plz answer this guys
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kvnmurty:
ok... i wil
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Draw the diagram.
AB = AC = 13 cm
Use Pythagoras theorem to find AD. In ΔABD,
AD² = AB² - BD² => AD = 5 cm
ΔABD and Δ ACE are similar as all the angles are same.. (AAA principle).
as ∠D = ∠E = 90°
as ∠DAB = ∠EAC = vertical angles at A
and hence, ∠DBA = ∠ACE (
and also AD ||AC and AB || AE.)
Ratios of sides => AC / AB = AE / AD = CE / BD
=> 13/13 = 5/AD = CE/12
so AD = 5 cm and CE = 12 cm.
That is very simple.
AB = AC = 13 cm
Use Pythagoras theorem to find AD. In ΔABD,
AD² = AB² - BD² => AD = 5 cm
ΔABD and Δ ACE are similar as all the angles are same.. (AAA principle).
as ∠D = ∠E = 90°
as ∠DAB = ∠EAC = vertical angles at A
and hence, ∠DBA = ∠ACE (
and also AD ||AC and AB || AE.)
Ratios of sides => AC / AB = AE / AD = CE / BD
=> 13/13 = 5/AD = CE/12
so AD = 5 cm and CE = 12 cm.
That is very simple.
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AB=AC=13 cm
Pythagoras therom and find AD
AD = 5cm
principle. AAA
Pythagoras therom and find AD
AD = 5cm
principle. AAA
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