Question

Plz answer this question

Answer 1

(b+c)^2/3bc

multiply N and D by a

ab^2 + ac^2 + 2abc)/ 3abc

(c+a)^2/3ac

multiply N and D by b

bc^2 + ba^2 + 2abc)/3abc

( a+ b)^2/3ab

multiply N and D by c

ca^2 + cb^2 + 2cab )/ 3abc

Add

ab^2 + ac^2 + 2abc + Bc^2 + ba^2 + 2abc + ca^2 + cb^2 + 2cab)/3abc

ab^2+ ba^2 + ac^2 + ca^2 + bc^2 + cb^2 + 2abc +2abc + 2abc)/3abc

ab( b+ a) + ca( c+ a) + bc( c+ b) + 6abc)/3abc

As a+ b+ c= 0

a+ b= - c

b+ c= -a

c+ a= - b

So

ab( -c) + ca( -b) + bc( -a) + 6abc)/ 3abc

- abc - abc - abc + 6abc )/ 3abc

-3abc + 6abc)/3abc

3abc/3abc

1