Math, asked by khan78600, 11 months ago

Plz answer this question

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Answered by buuny

1

Answer:

7+3^5/3+^5×3-^5/3-^5

=(7+3^5)(3-^5)/(3)^2-(^5)^2

=21-7^5+9^5-15/9-5

=21-7^5+9^5/4

=6-7^5+9^5/4

A=3

^5=^5

B=1

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