Question

plz answer this question.... ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝​

Answer 1

Answer:

79507

Step-by-step explanation:

64000(1+(7.5/100))^3

= 64000(1+(75/1000))^3

=64000(1+3/40)^3

=64000(43/40)^3

=64000(43*43*43/40*40*40)

=43*43*43

=79507

Answer 2

$\huge{\red{\underline{\underline{\rm{Answer:-}}}}}$

$\star{\blue{\underline{\bf{Given:-}}}}$

${\green{\tt{\implies Total\;population\;at\;present\;(P)=64,000}}}$

${\green{\tt{\implies Growth\;rate\;(r)=7.5\%}}}$

${\green{\tt{\implies Time\;(n)=3\;years}}}$

$\star{\blue{\underline{\bf{To\;Find:-}}}}$

${\green{\tt{\implies Population\;after\;three\;years.}}}$

$\star{\blue{\underline{\bf{Formula\;Used:-}}}}$

$\star{\boxed{\green{\tt{A=P\Bigg(1+\dfrac{r}{100}\Bigg)^{n}}}}}$

${\green{\textsf{Now, put the values in the formula, we get}}}$

${\green{\tt{\implies A=P\Bigg(1+\dfrac{r}{100}\Bigg)^{n}}}}$

${\green{\tt{\implies 64000\Bigg(1+\dfrac{7.5}{100}\Bigg)^{3}}}}$

${\green{\tt{\implies 64000\Bigg(\dfrac{100+7.5}{100}\Bigg)^{3}}}}$

${\green{\tt{\implies 64000\Bigg(\dfrac{107.5}{100}\Bigg)^{3}}}}$

${\green{\tt{\implies 64000\times 1.075\times 1.075\times 1.075}}}$

${\green{\tt{\implies 79,507}}}$

${\purple{\underline{\underline{\bf{\therefore Hence,\;population\;after\;three\;years\;would\;be\;79,507.}}}}}$