Question

What is the effect of increase in wire dia on the allowable stress value?

Answer 1

Let's go from basics. Stress is defined as force upon unit area. Now coming to the question the Force is Tensile load of 45kN and Area is the bar area. Assuming the bar is free of any ribs or irregularities the area of the bar will be pi() /4 * d^2 (d is diameter of rod) comes to 268.80 . Now considering load in Newton's (multiplying by 1000)

Stress in the rod = 45000/268.80 = 167.41 N/ or MPa (which is tensile stress in the bar) Hope this answers helps you how to calculate stress from force and area

Answer 2

Let's go from basics. Stress is defined as force upon unit area. Now coming to the question the Force is Tensile load of 45kN and Area is the bar area. Assuming the bar is free of any ribs or irregularities the area of the bar will be pi() /4 * d^2 (d is diameter of rod) comes to 268.80 sq.mm. Now considering load in Newton's (multiplying by 1000)

Stress in the rod = 45000/268.80 = 167.41 N/sq.mm or MPa (which is tensile stress in the bar) Hope this answers helps you how to calculate stress from force and area