Question

plz answer this question ​

Answer 1

$\huge\tt{\red{\underline{Given:}}}$

★$\dfrac{2sin^{2}63°+1+2sin^{2}27°}{3cos^{2}17°-2+3cos^{2}73°}$

$\huge\tt{\red{\underline{To\:\:Find:}}}$

★It's simplified value .

$\huge\tt{\red{\underline{Concept\:\:Used:}}}$

★We would use some formulas related to trigonometry.

$\huge\tt{\red{\underline{Answer:}}}$

We have,

$\implies\dfrac{2sin^{2}63°+1+2sin^{2}27°}{3cos^{2}17°-2+3cos^{2}73°}= y$ (say)

$\implies \dfrac{2sin^{2}63°+2sin^{2}27°+1}{3cos^{2}17°+3cos^{2}73°-2}= y$

$\implies \dfrac{2sin^{2}63°+2sin^{2}(90°-63°) +1}{3cos^{2}17°+3cos^{2}(90°-17°) -2}=y$

$\implies \dfrac{2sin^{2}63°+2cos^{2}63°+1}{3cos^{2}17°+3sin^{2}17°-2}=y$

$\large\green{\boxed{sin(90-\theta) =cos\theta}}$

$\large\red{\boxed{cos(90-\theta) =sin\theta}}$

$\implies \dfrac{2(sin^{2}63°+cos^{2}63°)+1}{3(cos^{2}17°+sin^{2}17°)-2}=y$

$\implies \dfrac{2×1+1}{3×1-2}=y$

$\large\purple{\boxed{sin^{2}\theta+cos^{2}\theta=1}}$

$\implies y = \dfrac{2+1}{3-2}$

$\implies y =\dfrac{3}{1}$

${\underline{\boxed{.°.\:\:y=3}}}$

Therefore the required answer is 3 .

Answer 2

Answer:

refer to the attachment please