Question

Two equal heavy spheres, each of radius r, are in equilibrium
within a smooth cup of radius 3r. The ratio of reaction
between the cup and one sphere and that between the two
sphere is Two equal heavy spheres, each of radius r, are in equilibrium
within a smooth cup of radius 3r. The ratio of reaction
between the cup and one sphere and that between the two
sphere is Two equal heavy spheres, each of radius r, are in equilibrium
within a smooth cup of radius 3r. The ratio of reaction
between the cup and one sphere and that between the two
sphere is

Answer 1

The question will be solved using the trigonometric formulas

The question depends on the law of motion and can be solved as -

We shall use the value of sin θ

= sinθ= 1/2  

Thus ,N1 sinθ= N2  

Therefore N1/ N2

               =1sinθ

               =2.

hence, the ratio of reaction between the cup and one sphere and that between the two sphere is 2