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I am in 11 class rn
I just gave 10 boards
so we have not read trigonometry of class 11
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sin2A=λsin2B
RHS
= λ+1 /λ-1
= (sin2A/sin2B)+1/ (sin2A/sin2B)- 1
= (sin2A+sin2B )/sin2A-sin2B)
=(2sin( 2A+2B /2)cos2 (2A-2B )) /(2sin( 2A-2B /2)cos2 (2A+2B ))
sin(A+B)cos(A−B) / sin(A−B)cos(A+B)
= tan(A+B) /tan(A-B)
=LHS
Hence proved.
Step-by-step explanation:
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