Math, asked by anonymous68115, 8 months ago

plz answer this question​

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Answered by CharmingPrince
15

{\huge{\green{\underline{\underline{\sf {\mathfrak{Answer}}}}}}}

{\bf{\orange{\underline{Given:}}}}

  • To \ prove \ 5+3\sqrt2 \ is irrational

{\bf{\orange{\underline{Solution:}}}}

\sf{\pink{\underline{\bigstar Let:}}}

5+3\sqrt2 \ is\ rational

\implies 5+3\sqrt2 = \dfrac{p}{q} \ \\ p \ and\ q \ are \ co \ primes \ and \ q \ is \ not 0

\implies 5 + 3 \sqrt2 = \dfrac{p}{q}

\implies 3\sqrt2 = \dfrac{p}{q} - 5

\implies \sqrt2 = \dfrac{p-5q}{3q}

As the LHS is rational , RHS is irrational , it is comcluded that our assumption is wrong and thus 5+3\sqrt2 is irrational.

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