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Step-by-step explanation:
|1 = |2 and |3 = |4 ....................1
in ∆ ABC , A + B + C = 180°. [ angle sum property ]
=> A + 1+2+3+4 = 180°
=> A + 2|2 + 2|4 = 180° [ from equation 1 ]
=> 2 [ |2 + |4 ] = 180° - A
=> |2 + |4 = (180 - A)/2 = 90° - A/2 .............2
in ∆ OBC, |O = 180° - ( |2 + |4 )
=> |O = 180° - [ 90° - A/2 ] [ from equation 2 ]
=> |O = 180° - 90° + A/2
=> |O = 90° + A/2 hence proved
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