plz answer this question
Attachments:
Answers
Answered by
1
Hi there!
cos θ = 0.6
cos θ = 6 / 10
cos θ = B / H = 6 / 10
→ B = 6
→ H = 10
Then,
P = √h² -b²
= √100 - 36
= √64
= 8
sin θ = P / H = 8 / 10
tan θ = P / B = 8 / 6
♦ ATQ,
L.H.S = 5 sin θ - 3tan θ
= 5x 8 / 10 - 3x 8 / 6
= 40 / 10 - 24 / 6
= 4 - 4
= 0 = R.H.S
[ HENCE PROVED. ]
Hope it helps! :)
cos θ = 0.6
cos θ = 6 / 10
cos θ = B / H = 6 / 10
→ B = 6
→ H = 10
Then,
P = √h² -b²
= √100 - 36
= √64
= 8
sin θ = P / H = 8 / 10
tan θ = P / B = 8 / 6
♦ ATQ,
L.H.S = 5 sin θ - 3tan θ
= 5x 8 / 10 - 3x 8 / 6
= 40 / 10 - 24 / 6
= 4 - 4
= 0 = R.H.S
[ HENCE PROVED. ]
Hope it helps! :)
Similar questions