plz answer this question...
Answers
Answer:
Hi,
Explanation:
Resistance of 1 Bulb = 990
Total cost of Energy Consumed = Rs. 1.155
Power =
Work Done = Energy
Power =
Energy = Vlt
Time = t
Power =
Power = VI
V = 330 V
P = 110 W
T = 5 hrs
Number of Bulbs = 3
Cost of 1 unit of Energy = 70 paise
P =
I =
I =
I = A
V = IR
R =
R = 330 ÷
R = 330 × 3
R = 990
Resistance of 1 Bulb is 990 Ohm
Energy = VIt
E = VIt
E = 330 × 1/3 × 5 wh
E = 550 wh
Energy consumed by 3 Bulbs = 3 × Energy consumed by 1 bulb.
Energy consumed by 3 Bulbs = 3 × 550 wh
Energy consumed by 3 Bulbs = 1650 wh
1 kWh = 1000 wh
1 Wh = 1/1000 kWh
1650 Wh = 1650/1000 kWh
1650 Wh = 1.65 kWh
Energy consumed by 3 Bulbs is 1650 Wh or 1.65 kWh.
70 paise = RS. 0.7
Cost of one unit of Energy = Rs. 0.7
Cost of 1.65 kWh of energy = RS. 1.155
Hope it will help you ❤️❤️❤️
Answer:
Rs : 1.155
have a nice day