Math, asked by toonstertamil, 2 months ago

plz answer this question​

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Answered by senboni123456
1

Step-by-step explanation:

We have,

 \rm \:  \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} }  = a + b \sqrt{3}  \\

 \rm \:   \implies\frac{(5 + 2 \sqrt{3})(7 - 4 \sqrt{3} ) }{(7 + 4 \sqrt{3} )(7 - 4 \sqrt{3} )}  = a + b \sqrt{3}  \\

 \rm \:   \implies\frac{5 (7 - 4 \sqrt{3} ) +2 \sqrt{3}(7 - 4 \sqrt{3})  }{(7)^{2}  - (4 \sqrt{3} ) ^{2} }  = a + b \sqrt{3}  \\

 \rm \:   \implies\frac{35 - 20 \sqrt{3} +14 \sqrt{3}- 24  }{49  - 48  }  = a + b \sqrt{3}  \\

 \rm \:   \implies\frac{11-  6 \sqrt{3}  }{1 }  = a + b \sqrt{3}  \\

 \rm \:   \implies11-  6 \sqrt{3}   = a + b \sqrt{3}  \\

On comapring,  \rm\:a=11\:\:\&\:\:b=-6

Answered by arnimaanuragmishra
0

Answer:

Resolve to perform what you ought; perform without fail what you resolve.

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