Question

plz answer this question​

Answer 1

Step-by-step explanation:

We have,

$\rm \: \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = a + b \sqrt{3}$

$\rm \: \implies\frac{(5 + 2 \sqrt{3})(7 - 4 \sqrt{3} ) }{(7 + 4 \sqrt{3} )(7 - 4 \sqrt{3} )} = a + b \sqrt{3}$

$\rm \: \implies\frac{5 (7 - 4 \sqrt{3} ) +2 \sqrt{3}(7 - 4 \sqrt{3}) }{(7)^{2} - (4 \sqrt{3} ) ^{2} } = a + b \sqrt{3}$

$\rm \: \implies\frac{35 - 20 \sqrt{3} +14 \sqrt{3}- 24 }{49 - 48 } = a + b \sqrt{3}$

$\rm \: \implies\frac{11- 6 \sqrt{3} }{1 } = a + b \sqrt{3}$

$\rm \: \implies11- 6 \sqrt{3} = a + b \sqrt{3}$

On comapring, $\rm\:a=11\:\:\&\:\:b=-6$

Answer 2

Answer:

Resolve to perform what you ought; perform without fail what you resolve.