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Step-by-step explanation:
Solution
Given- O is the centre of a circle of which the chords AB and CD intersect at E.
∠BAC=45
o
and ∠BED=120
o
.
To find out- ∠ABD=?
Solution- ∠BAC=45
o
=∠BDC
Since both the angles are on the same chord BC ( the angles, subtended by a chord to different points of the circumference are equal).
So in ΔBDE, we have
∠EBD or ∠ABD=180
o
−(∠BED+∠BDE)=180
o
−(120
o
+45
o
)=15
o
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