Plz answer this question! 50 points
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This is the graph of f(x).
f(x) = 1/x is definitely one to one by the Horizontal Line Test. Any horizontal line drawn cuts the graph at only one point.
The function is also onto because for any y = 1/x in codomain R0, there exists an x in the domain R0
Let g: N ---> R0 be the other function g(x).
The graph remains the same hence the function g(x) is still one to one.
However for any y' in codomain R0 such as a decimal 8.5 there doesn't exist any x in domain N.
f(x) = 1/x is definitely one to one by the Horizontal Line Test. Any horizontal line drawn cuts the graph at only one point.
The function is also onto because for any y = 1/x in codomain R0, there exists an x in the domain R0
Let g: N ---> R0 be the other function g(x).
The graph remains the same hence the function g(x) is still one to one.
However for any y' in codomain R0 such as a decimal 8.5 there doesn't exist any x in domain N.
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DiamondBeauty1111:
Thnx
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f(x1)=f(x2);then x1=x2 then we can say it is one one
put in given function x value is x1andx2
f(x1)=1/x1andf(x2)=1/x2 as given f(x1)=f(x2)
so 1/x1=1/x2 by cross multiply we get x1=x2 so f(x) is one one function
range of function is R0 by graph of function so onto
when it replace it is then result same true
put in given function x value is x1andx2
f(x1)=1/x1andf(x2)=1/x2 as given f(x1)=f(x2)
so 1/x1=1/x2 by cross multiply we get x1=x2 so f(x) is one one function
range of function is R0 by graph of function so onto
when it replace it is then result same true
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