Question

plz answer this question 50 points

Answer 1

here ...............

I = 1 A
time = 15 sec

We know that ,

$1amp = \frac{1coloumb}{1sec}$

$1 = \frac{coloumb}{15}$

1coloumb of charge of electron= 15C.

$no. \: of \: electrons = \frac{coloumb}{ampere}$

$no. \: of \: electrons \: = \frac{15}{1}$
____________________________
Therefore,
The no. of electrons flowing are 15 .
____________________________
$hope \: \: this \: \: helps$

Answer 2

We have,

|=1A time=15 sec

We know that ,

1coloumb lsec

lamp = 1 c / s

1 = coloumb /15

1co|oumb of charge of electron: 15C.

coloumb ampere

no. of electrons = coulomb / ampere

no. of electrons = 15 /1

Therefore, The no. of electrons flowing are 15