Question

plz answer this question

Answer 1

Heya ✌✌
Here is u r Ans ➡➡➡
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$= \frac{x}{4y {}^{2} } - \frac{2}{3} + \frac{4y {}^{2} }{9x {}^{2} }$

$= expand \: the \: fraction \: to \: get \: the \: least \: common \: denominator$

$= \frac{9x {}^{2} \times x }{9x {}^{2} \times 4y {}^{2} } - \frac{12x {}^{2} \times y {}^{2} \times 2 }{12x {}^{2} y {}^{2} \times 3} + \frac{4y {}^{2} \times 4y {}^{2} }{4y {}^{2} \times 9x {}^{2} }$

$= \frac{9x {}^{3} }{9x {}^{2} \times 4y {}^{2} } - \frac{12x {}^{2} y {}^{2} \times 2}{12x {}^{2}y {}^{2} \times 3 } + \frac{4y {}^{2} \times 4y {}^{2} }{4y {}^{2} \times 9x {}^{2} }$

$= \frac{9 \times {}^{3} - 24x {}^{2} y {}^{2} + 16y {}^{4} }{36x {}^{2} y {}^{2} }$

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Hope This Helps u ☺