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Let (5-y^2-y ) = length
Let x = breadth
Area of rectangle = length × breadth
5(y+3)(y^2-16) = 5(y^2-y-12)× x
(5y+ 15)(y^2-16) = 5(y^2-y-12) × x
5y^3-80y +15y^2-240 = 5(y^2-y-12) × x
5y^3+ 15y^2-80y-240 = 5(y^2-y-12)× x
5y^3+15y^2-80y-240/5(y^2-y-12) = x
(Y+4) = x
Hence,D is the correct option
Hope it helps you ...
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