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theata = 17π/3=(5+2/3)π
5π+2π/3=6π-π/3
tan theta - cot theata =tan theta -1/ tan theata
tan(6π-π/3)
-1/tan 6π-π/3
5π+2π/3
6π-π/3
tan(1-π/3).1/tan(-π/9)
√3-1/√3=3-1/-√3=-2/3
saqib44:
You are rught
right
in which class r u studying
10
Which book r u refering
ncert
Kya ap mera test le rhi thi
No
ok
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