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take total current as 6I
then if we consider the ACBA loop then
apply kkirchhoff's law of voltage
so we get 2I×R +I×R+2I×R=E
or, 5IR=E....(1)
now ,if the effective resistance between A B become r
then 6I×r=E...(2)no.
from 1no. and 2no. equation we get
5IR=6Ir
or,r /effective resistance=5R/6
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