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⭐Using 3rd equation of motion :
⭐v² - u² = 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance covered
⭐Acc . to question:
✔️u initial velocity of train = 90 km/ hr
= 25 m/s
✔️acceleration a = - 0.5 m / s²
✔️final velocity v = 0 ( rest)
So,
✔️0 - ( 25 )² = 2 x - 0.5 x s
✔️s = 625/ 1 m
✔️s = 625 m
Hence train will cover 625 m before coming to rest.
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