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In a triad Atomic mass of middle element is average of other two elements.
B = (A + C) / 2
150 = (A + 200) / 2
300 = A + 200
A = 100
Atomic mass of A is 100
B = (A + C) / 2
150 = (A + 200) / 2
300 = A + 200
A = 100
Atomic mass of A is 100
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