Question

plz answer this question fastly

Answer 1

The specific heat of water is 1 calorie/gram °C = 4.186 joule/gram
Q=msdT
q
- heat absorbed
m
- the mass of the sample
s
- the specific heat of the substance
Δ
T
- the change in temperature, defined as final temperature minus initial temperature
Q=100×4.186×(50-20)
Q=12,558J
Q=12.558kJ