Question

plz answer this question for me I have maths exam tomo4and no fake answers plz

question 20

Answer 1

Heya !!!


here is your answer !!!


given that


2/3 zeros of polynomial

therefore ,


on putting the value of zeroes in polynomial we get

a ( 2/3 ) ² + 7 * 2/ 3. + b = 0.


=> 4 / 9 * a + 14 / 3 + b = 0


4a + 42 +. 9b = 0. ----------------(1)



now ,

on putting the value of second zeros in polynomial we get

a (-3 ) ² + (-3 ) *7 + b = 0


=> 9a -21 + b = 0 -----------------(2)


from equation 1 and 2 we get



4a + 42 + 9b = 0

and
9a -21 + b = 0


or b = 21 -9a


on putting the value of b in equation 1 we get

4a + 42 + 9 (21 - 9a ) = 0


=> 4a + 42 + 189 -81a

=> - 77a + 231. = 0


a => 3


hence , b = 21 - 9a

= >. 21 - 9 *3

=> 21 -27


=> -6




hence , a = 3


and b = -6



hope it helps you dear !!!


thanks !!!!

Answer 2

Here is your answer :-

a = 3 and b = -6