Question

Plz answer this question from exponents​

Answer 1

Step-by-step explanation:

given x^1+3+5+7........999

= x^ sum of odd numbers from 1 to 999

for that arithmetic progression is used

a= first term +(n-1)d

999= 1+(n-1)2

998/2=n-1

449=n-1

n = 500

sum of 500 odd terms = n/2(a+l)

= 500/2(1000)

= 250000

similarly sum of 500 even terms= 500/2(2+1000)

500×501

= 250500

now, x^250000/x^250500= x^ 250000-250500

= x^-500

= 1/ x^500

there answer is 1/x^500

mark me the brainliest