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1)T=M*V/F
=50*0.25/200
=0.0625
as the mass is in kg converting it into grams,,,
=0.0625*1000
=62.5 sec
Speed= dist/time
s*t=d
0.25*62.5=15.625m=distance
W=f*s
=200*15.625 = 3125 Joules of work is done
2)rate of work done=w/t=3125/62.5= 50 Watt
3) net force=applied force - frictional force
once attained a velocity of 0.25m/s it attained constant state so net force became zero,
therefore applied force=frictional force
therefore, frictional force =200 N
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