Question

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Answer 1

Answer:

OA=OB(RADII OF THE SAME Circle)

Angle OBA=40degree

In Triangle OAB by asp

AngleAOB=180-80=100

We know angle 2ACB=AngleAOB

ACB =100÷2 =50 degree

Step-by-step explanation:

In △OAB,

OA = OB [radii of same circle]

∠OBA = ∠OAB = 40° [∠s opp. to equal sides in a △ are equal]

Now, ∠OAB + ∠AOB + ∠OBA = 180° [angle sum properly of a △]

⇒ 40° + ∠AOB + 40° = 180°

⇒ ∠AOB = 100°

Therefore, ∠ACB = 50° [∵ angle subtended by an arc at the centre is double the angle subtended by it at the remaining part of the circle]

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Answer 2

AOB = 2ACB

then AOB = 80°

And the angle OAB = angle OBA

when you prove it congruence

so Angle OAB = 50°