Plz answer this question it is urgent
Sec^4ø-sec^2ø=tan^2ø+tan^4ø
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Step-by-step explanation:
Left side
- sec^4x - sec^2x
= 1/cos^4x - 1/cos^2x
take l.c.m. .....
1 - cos^2x/ cos^ 4x
sin^2x/ cos^4x
tan^2x (1/cos^2x)
now we apply the trig identity ...i.e..
1/cos^2x = (1 + tan^2x )
now....left side is...
tan^2x (1+ tan^2x ) = tan^4x + tan^2x
hence proved.....
thats ur answer....i jst hope that will hlp uhh....
if uh r satisfied with this answer....then mark this as a brainlist .....
thnkew....
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