Question

plz answer this question its urgent

Answer 1

Answer:

2/CosA

Step-by-step explanation:

cosA/(1+SinA) + (1+SinA)/CosA

lets Multiply and divide by 1-sinA

{(1-SinA)CosA}/{(1+SinA)(1-SinA)}   +  {(1-SinA)(1+SinA)}/{(1-SinA)(CosA)}

{(1-SinA))CosA))/{(1+SinA)(1-SinA)} + (1-Sin²A)/{(1-SinA)(CosA)}

{(1-SinA))CosA))/{(1+SinA)(1-SinA)}+ (Cos²A)/{(1-SinA)(CosA)}

{(1-SinA))CosA))/({(1+SinA)(1-SinA)} + (CosA)/(1-SinA)

{1/(1+SinA)(1-SinA)}*{(1-SinA))CosA))+(1+SinA)CosA)

{1/(1-Sin²A)}*CosA*2

2CosA/Cos²A

2/CosA