Question

plz answer this question . plz

Answer 1

Answer:

∆ACP ~ ∆BDP (Since A-A-A)

So AC/BD =AP/BP=PC/PD

Since AP=PB , AP/PB=1

(x+y)/5 = 1 = 2x/3y

x+y=5 ---------(1)

2x=3y -----------(2)

Solving 1 and 2 x=3, y=2

Answer 2

Answer:

x=3; y=2

Step-by-step explanation:

angle ACP=angle BDP

angle APC=angle BPD

AP=BP

∆APC=∆BPD

DP=CP

3y=2x

y= 2x/3

AC=BD

x+y=5

x+(2x/3)=5

5x/3=5

x=3

y=2*3/3=2