Question

plz answer this question step by step??

Answer 1

1 day work of AB = 1/10

1 day work of BC = 1/15

1 day work of CA = 1/20

Adding them together

A + B + B + C + C + A = 1/10 + 1/15 + 1/20

2A + 2B + 2C = 1/10 + 1/15 + 1/20

2 (A+B+C) = (6+4+3)/60

2 (A+B+C) = 13/60

A+B+C = 13/120

so we get 1 day work of ABC together = 13/120

Now,

1 day work of C would be = 1 day work of ABC - 1 day work of AB

1 day work of C = 13/120 - 1/10

= (13-12)/120

= 1/120

So C would complete whole work alone in 120 days

1 day work of A would be = 1 day work of ABC - 1 day work of BC

1 day work of A = 13/120 - 1/15

= (13-8)/120

= 5/120

= 1/24

So A would complete whole work alone in 24 days

1 day work of B would be = 1 day work of ABC - 1 day work of CA

1 day work of B = 13/120 - 1/20

= (13-3)/120

= 10/120

= 1/12

So B would complete whole work alone in 12 days

A takes 24 days working alone

B takes 12 days working alone

C takes 120 days working alone