plz answer this stepwize
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force=mass×accelaration
for A,F=m×a(A)
for B,F=3m×a(B)
thus equating,m×a(A)=3m×a(B)
=>a(A)=3a(B)
thus magnitude of acc. of A is 3 times that of B
for A,F=m×a(A)
for B,F=3m×a(B)
thus equating,m×a(A)=3m×a(B)
=>a(A)=3a(B)
thus magnitude of acc. of A is 3 times that of B
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Mass of block A = m
Mass of block B = 3m
Acceleration of block A and B be a and a’ respectively.
Use F = ma for both the blocks.
• For block A
a = F/m
• For block B
a’ = F/(3m)
Compare a and a’
a’ = a/3
a = 3a’
Hence option (a) is correct.
Mass of block B = 3m
Acceleration of block A and B be a and a’ respectively.
Use F = ma for both the blocks.
• For block A
a = F/m
• For block B
a’ = F/(3m)
Compare a and a’
a’ = a/3
a = 3a’
Hence option (a) is correct.
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