plz answer this urgently
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Sudhir1188:
ans is 30 degree
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3x + 10 = 60° + 40°
3x + 10 = 100°
3x = 90°
x = 30°
3x + 10 = 100°
3x = 90°
x = 30°
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draw a line parallel to AB and CD. name it EF
40+ angle from by AE = 180( interior angle on same side of transversal)
Angle =140
now from downside
angle formed AE is 120
180-60
therefore they together form 140+120=260
3x+10+260=360( angle from a point)
3x+10=100
3x=90
x=30
hope it helps
40+ angle from by AE = 180( interior angle on same side of transversal)
Angle =140
now from downside
angle formed AE is 120
180-60
therefore they together form 140+120=260
3x+10+260=360( angle from a point)
3x+10=100
3x=90
x=30
hope it helps
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