Plz answer thw question in the image...My exam Is there..
Attachments:
Divyankasc:
are they esy ? or hard ?
if you already know that "while coming down, the speed when it passes the edge of cliff is same as initial velocity(but in downward direction), then it is easy"
otherwise it is lengthy
yeah i know.................I did not see it .........But i got it on my own
it's not very hard, but not easy too
nice!:))
hmmm....One question was like that onlt...That its thrown up with velocityy....I had to solve longgg along with variables
for u everthing which i post wouldbe esy..u r of class 11 na
sort of :P
http://brainly.in/question/216103
answer it
answer it
Answers
Answered by
3
given,
initial velocity = 10 m/s
time taken = 1.2 sec
acceleration = 9.8 m/s^2
therefore distance,
s = ut+1/2 at^2
s= 10*1.2 + 1/2 * 9.8 * (1.2 )^2
s = 12 + 4.9 * 1.44
s = 12 + 7.056
s = 19.056
therefore option (d) 19 m is the answer according to me.
i hope that this will help u.....................^_^
initial velocity = 10 m/s
time taken = 1.2 sec
acceleration = 9.8 m/s^2
therefore distance,
s = ut+1/2 at^2
s= 10*1.2 + 1/2 * 9.8 * (1.2 )^2
s = 12 + 4.9 * 1.44
s = 12 + 7.056
s = 19.056
therefore option (d) 19 m is the answer according to me.
i hope that this will help u.....................^_^
option (D)
it is mentioned in the question
it is mentioned that it is thrown upwards with that velocity..Caught u
so
let it be i understood
ok
the speed of the stone upwards, is the same when the stone falls back to the same height... ie., at the edge of the cliff..
the stone travels up at 10m/s vertical component, then it becomes 0.. when it falls down, it regains the same speed at the same altitude..
you must mention this point in the answer
yeah that what i asked u pahi...
Similar questions