Question

plz answer with explanation!!!!!urgent!!!!!​

Answer 1

Answer:

0

Step-by-step explanation:

Let 3^x be 'a' ....for simplicity

so 3^-x=1/a

SO BY GIVEN EQUATION....

a+1/a=2

(a^2+1)/a=2

or

a^2- 2a + 1=0

a^2- a -a + 1=0

a( a-1) -1(a-1)=0

(a-1)(a-1)=0

⇒a=1

BUT by definition a=3^x

⇒ x=0