Question

Plz anyone can say me this answer!​

Answer 1

Answer:

The Normal is an imaginary line which is perpendicular to the reflection surface .

The angle of reflection is always equal the angle of incidence, which is the angle that the incoming ray, called incident ray makes with the normal.... In this case angle IOR = 90-30= 60.

Explanation:

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Answer 2

Diagram :-

$\setlength{\unitlength}{1mm}\begin{picture}(0,0)\qquad\thicklines\put(0,0){\line(3,0){4cm}}\put(19.6,0){\line(0,3){1.9cm}}\put(19,20){\sf\footnotesize N}\put(19.6,0){\vector(3,4){1cm}}\put(19.6,0){\vector(3,-4){1cm}}\put(26,-4){ \alpha }\qbezier(22.1,-3)(26.5,-4)(24,0)\qbezier(19.6,3)(21,5)(21.4,2.2)\put(20,5.7){ \sf\footnotesize 30^\circ }\multiput(19.6,0)(0,-2){7}{\line(0,-3){1mm}}\put(18.7,-16){\sf\footnotesize N}\put(10,13){\line(3,-4){1cm}}\qbezier(18,2.5)(18,5)(19.7,2.8)\put(-2,19){\sf\small Angle_{\bf i} \vector(3,-4){3mm}}\end{picture}$

Solution :-

Here ,

• 30° is angle of reflection .
• $\boldsymbol\alpha$ is angle of glancing .

Since , angle of reflection is 30° , angle of incidence is also 30°

$\boldsymbol\because$ Angle if incident = Angle of reflection .

Now , the mirror is straight , so angle on the mirror = 180°

Now , drawing a normal below the mirror in dotted . So, the normal is perpendicular to the mirror = 90° . So, angle of incidence and angle with the normal are equal.

$\boldsymbol\because$ Opposite angles are equal .

• Angle with the normal = 30°

Now , finding angle of glancing

$\to \alpha$ + 30° = 90°

$\to\alpha$ = 90° - 30°

$\to\boldsymbol \alpha$ = 60°

Hence , angle of glancing = 60°