Question

plz.. anyone who can solve any of these problems or all...

Answer 1

16..1..a2+24-10a/a-5

Answer 2

16.

a(a-5)=1

a^2-5a = 1 -eq1

Dividing eq1 by a on both sides

a^2/a -5a/a =1/a

a-5=1/a

a-1/a=5 ans (i)

(ii)

(a-1/a)^2 =a^2+(1/a)^2 - 2a×1/a

5^2 = a^2+1/a ^2-2

25 +2= a^2+ 1/a^2

a^2+1/a^2=27

(a+1/a)^2 =a^2 +1/a^2 +2 ×a×1/a

(a+1/a)^2= 27+2

(a+1/a)^2 =29

(a+1/a)= √29

(iii)

(a^2 -1/a^2)= (a+1/a)(a-1/a)

= √29×5=5√29

...( ^2)means a number to the power 2