Question

plz as soon as possible u can alive plz ​

Answer 1

Step-by-step explanation:

gave any questions please

Answer 2

Answer:

» Given:

${\frac{p}{q} = (\frac{7}{4})^2 × (\frac{4}{9})^2}\\ \\ \\</p><p>by\:simplifying \\ \\ \\</p><p>\frac{p}{q} = (\frac{7}{9})^2$

Similarly,

$\frac{q}{p} = (\frac{9}{7})^2$

» To find,

$(\frac{p}{q})^2 × (\frac{q}{p})^3$

» By putting values

${[(\frac{7}{9})^2]^2 × [(\frac{9}{7})^2]^3}$

${\pink{\boxed{Law - (a^m)^n = a^{mn} }}}$

${(\frac{7}{9})^4 × (\frac{9}{7})^6}$

=${\frac{7^4 × 9^6}{7^6 × 9^4}}\\ \\ \\ </p><p></p><p>{\blue{\boxed{Law - \frac{a^m}{a^n} = a^{m-n} }}}$

= $\frac{9^2}{7^2}$

= ${\green{\boxed{[\frac{9}{7}]^2}}}$