Question

Plz can anyone solve this 2nd, 3rd and 4rd part? Thanks for help

Answer 1

Heya...
Here is your answer --

2. Outer Base angle = 60° and 80°
=> Base angle of the pentagon = 120° and 100° (Linear pair with the outer base angle)

Now, 40+x+x+100+120 = 540 (Angle sum)
=> 40+2x+220 = 540
=> 2x+260 = 540
=> 2x = 280
=> x = 280/2 = 240
Hence, x is 240°

3. Outer base angle = 90°
Second base angle of quadrileteral = 90° (linear pair with the outer base angle)

Now, 90+60+110+x = 360 (angle sum)
=> x+260 =360
=> x = 100

Hence, x is 100°

4. Outer base angle = x
Base angle of quadrilateral = 180-x (linear pair)
Other base angle = 90°

Now, 110+83+90+(180-x) = 360 (angle sum)
=> 283+(180-x) = 360
=> 463-x = 360
=> -x = 360-463
=> x = 103

Hence, x is 103°.

HOPE IT HELPS...!!