plz can someone please help me
Attachments:
Answers
Answered by
1
Answer:
Angle y = 1/2 angle AOB
(Angle subtended by an arc at the centre is twice that of the angle subtended at the circumference)
So y = 1/2 × 110 = 55°
Notice BEAC is a cyclic quadrilateral
z = 180 - y = 180 - 55 = 125°
(Opposite Angles in a cyclic quadrilateral sum upto 180)
angle BOA + angle AOD = 180° (supplementary angles)
So angle AOD = 180 - 110 = 70°
And Angle x = 70/2 =35°
(Angle at circumference is half angle at centre when arcs are equal)
Answered by
0
Answer:
hii dear
hear is your answer
Attachments:
Similar questions