Question

plz could you plz help me to solve this problem plz plz​

Answer 1

Answer:

teacher nhi banunge pr boubth h to solution de sakte hu

answer h

let the height of Tower = PQ= h meter

let the distance =BQ= x metet

in triangl PQB

tan45 degree= PQ/BQ

1= h/x

x=h.... (1)

In triangle PQA

tan30degree =PQ/AQ

1/3 = h/20+x [root lagna h 3 me bhulna mt]

root 3x=20+x

root 3x=20+y

root 3-h=20

h(root 3-1)=20

h=20/root 3 -1

20/1.732-1 [(root 3 ke value

hote h 1.732)]

20/0.732

27.32mete