Plz do both of them.
Attachments:
Answers
Answered by
2
1.
(-3 / 4a^2b^3 ) × (2ab^3/3)
= -b/2a
2.( 12x^2y^2 -6x^2+8y-4xy)÷6xy
Here all you need to do is just put 6xy in the denominator
= ( 12x^2y^2/6xy) - (6x^2/6xy) +(8y/6xy) -(4xy/6xy)
= 2xy - (x/y) +( 4/3x) - (2/3)
(-3 / 4a^2b^3 ) × (2ab^3/3)
= -b/2a
2.( 12x^2y^2 -6x^2+8y-4xy)÷6xy
Here all you need to do is just put 6xy in the denominator
= ( 12x^2y^2/6xy) - (6x^2/6xy) +(8y/6xy) -(4xy/6xy)
= 2xy - (x/y) +( 4/3x) - (2/3)
Saanvipriya:
thank you sooooo much
solved my problem
You're welcome tooooo much..
Its my pleasure
Similar questions