Question

plz do it fasttt ?????? ​

Answer 1

$\bigstar$ Given:-

A car initially was at rest and increased its velocity to 8 ms⁻¹ in 80 s

$\bigstar$ To Find:-

The acceleration

$\bigstar$ Solution

We know that;

Equation of Motion

$\red{\rm \longrightarrow v=u+at}$

Here;

u = initial velocity

v = final velocity

a = acceleration

t = time

According to the question

We are asked to find the acceleration

Therefore:-

We must find "a"

Given that;

A car initially was at rest and increased its velocity to 8 ms⁻¹ in 80 s

Hence;

u = 0 ms⁻¹ [initially at rest]

v = 8 ms⁻¹

t = 80 s

Substituting the values

We get:

$\blue{\rm \longrightarrow 8=0+(a \times 80)}$

$\green{\rm \longrightarrow 8=80a}$

$\purple{\rm \longrightarrow 80a=8}$

$\orange{\rm \longrightarrow a=\dfrac{8}{80} \ ms^{-2}}$

Hence:

$\pink{\rm \longrightarrow a=0.1 \ ms^{-2}}$

Therefore;

$\checkmark$ Acceleration = 0.1 ms⁻².

_________________________________________________________________________________________________________________

Answer 2

Answer:

car initially was at rest and increased its velocity to 8 ms⁻¹ in 80 s

\bigstar★ To Find:-

The acceleration

\bigstar★ Solution

We know that;

Equation of Motion

\red{\rm \longrightarrow v=u+at}⟶v=u+at

Here;

u = initial velocity

v = final velocity

a = acceleration

t = time

According to the question

We are asked to find the acceleration

Therefore:-

We must find "a"

Given that;

A car initially was at rest and increased its velocity to 8 ms⁻¹ in 80 s

Hence;

u = 0 ms⁻¹ [initially at rest]

v = 8 ms⁻¹

t = 80 s

Substituting the values

We get:

$⟶8=0+(a×80)</p><p></p><p>\green{\rm \longrightarrow 8=80a}⟶8=80a</p><p></p><p>\purple{\rm \longrightarrow 80a=8}⟶80a=8</p><p></p><p>\orange{\rm \longrightarrow a=\dfrac{8}{80} \ ms^{-2}}⟶a=808 ms−2</p><p></p><p>Hence:</p><p></p><p>\pink{\rm \longrightarrow a=0.1 \ ms^{-2}}⟶a=0.1 ms−2</p><p></p><p>Therefore;</p><p></p><p>\checkmark✓ Acceleration = 0.1 ms⁻</p><p></p><p>$