plz do it in easy method it's class 10 maths
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area of segment = area of the sector - triangle.-----------1
first calculate area of sector.
area of sector= theta / 360 * pi * r^2
theta = 120
=120 / 360 * 22/7 * 21* 21
=22 * 21
=462
area of triangle = r^2 *sin∅/2
=21 * 21 * sin(60)
=21 * 21 * √3/2
=441√3 /4
with 1,
area of segment = area of the sector - triangle.
=462 - 441√3/4
= 21/4 ( 88 - 21√3)
hope it helps!!!!
first calculate area of sector.
area of sector= theta / 360 * pi * r^2
theta = 120
=120 / 360 * 22/7 * 21* 21
=22 * 21
=462
area of triangle = r^2 *sin∅/2
=21 * 21 * sin(60)
=21 * 21 * √3/2
=441√3 /4
with 1,
area of segment = area of the sector - triangle.
=462 - 441√3/4
= 21/4 ( 88 - 21√3)
hope it helps!!!!
rowdyaneek:
hi
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